Haskell programmers care about the correctness of their software and they specify correctness conditions in the form of equations that their code must satisfy. They can then verify the correctness of these equations using equational reasoning to prove that the abstractions they build are sound. To an outsider this might seem like a futile, academic exercise: proving the correctness of small abstractions is difficult, so what hope do we have to prove larger abstractions correct? This post explains how to do precisely that: scale proofs to large and complex abstractions.

Purely functional programming uses composition to scale programs, meaning that:

- We build small components that we can verify correct in isolation
- We compose smaller components into larger components

If you saw "components" and thought "functions", think again! We can compose things that do not even remotely resemble functions, such as proofs! In fact, Haskell programmers prove large-scale properties exactly the same way we build large-scale programs:

- We build small proofs that we can verify correct in isolation
- We compose smaller proofs into larger proofs

The following sections illustrate in detail how this works in practice, using `Monoid`

s as the running example. We will prove the `Monoid`

laws for simple types and work our way up to proving the `Monoid`

laws for much more complex types. Along the way we'll learn how to keep the proof complexity flat as the types grow in size.

#### Monoids

Haskell's Prelude provides the following `Monoid`

type class:

```
class Monoid m where
mempty :: m
mappend :: m -> m -> m
-- An infix operator equivalent to `mappend`
(<>) :: Monoid m => m -> m -> m
x <> y = mappend x y
```

... and all `Monoid`

instances must obey the following two laws:

```
mempty <> x = x -- Left identity
x <> mempty = x -- Right identity
(x <> y) <> z = x <> (y <> z) -- Associativity
```

For example, `Int`

s form a `Monoid`

:

```
-- See "Appendix A" for some caveats
instance Monoid Int where
mempty = 0
mappend = (+)
```

... and the `Monoid`

laws for `Int`

s are just the laws of addition:

```
0 + x = x
x + 0 = x
(x + y) + z = x + (y + z)
```

Now we can use `(<>)`

and `mempty`

instead of `(+)`

and `0`

:

```
>>> 4 <> 2
6
>>> 5 <> mempty <> 5
10
```

This appears useless at first glance. We already have `(+)`

and `0`

, so why are we using the `Monoid`

operations?

#### Extending Monoids

Well, what if I want to combine things other than `Int`

s, like pairs of `Int`

s. I want to be able to write code like this:

```
>>> (1, 2) <> (3, 4)
(4, 6)
```

Well, that seems mildly interesting. Let's try to define a `Monoid`

instance for pairs of `Int`

s:

```
instance Monoid (Int, Int) where
mempty = (0, 0)
mappend (x1, y1) (x2, y2) = (x1 + x2, y1 + y2)
```

Now my wish is true and I can "add" binary tuples together using `(<>)`

and `mempty`

:

```
>>> (1, 2) <> (3, 4)
(4, 6)
>>> (1, 2) <> (3, mempty) <> (mempty, 4)
(4, 6)
>>> (1, 2) <> mempty <> (3, 4)
(4, 6)
```

However, I still haven't proven that this new `Monoid`

instance obeys the `Monoid`

laws. Fortunately, this is a very simple proof.

I'll begin with the first `Monoid`

law, which requires that:

`mempty <> x = x`

We will begin from the left-hand side of the equation and try to arrive at the right-hand side by substituting equals-for-equals (a.k.a. "equational reasoning"):

```
-- Left-hand side of the equation
mempty <> x
-- x <> y = mappend x y
= mappend mempty x
-- `mempty = (0, 0)`
= mappend (0, 0) x
-- Define: x = (xL, xR), since `x` is a tuple
= mappend (0, 0) (xL, xR)
-- mappend (x1, y1) (x2, y2) = (x1 + x2, y1 + y2)
= (0 + xL, 0 + xR)
-- 0 + x = x
= (xL, xR)
-- x = (xL, xR)
= x
```

The proof for the second `Monoid`

law is symmetric

```
-- Left-hand side of the equation
= x <> mempty
-- x <> y = mappend x y
= mappend x mempty
-- mempty = (0, 0)
= mappend x (0, 0)
-- Define: x = (xL, xR), since `x` is a tuple
= mappend (xL, xR) (0, 0)
-- mappend (x1, y1) (x2, y2) = (x1 + x2, y1 + y2)
= (xL + 0, xR + 0)
-- x + 0 = x
= (xL, xR)
-- x = (xL, xR)
= x
```

The third `Monoid`

law requires that `(<>)`

is associative:

`(x <> y) <> z = x <> (y <> z)`

Again I'll begin from the left side of the equation:

```
-- Left-hand side
(x <> y) <> z
-- x <> y = mappend x y
= mappend (mappend x y) z
-- x = (xL, xR)
-- y = (yL, yR)
-- z = (zL, zR)
= mappend (mappend (xL, xR) (yL, yR)) (zL, zR)
-- mappend (x1, y1) (x2 , y2) = (x1 + x2, y1 + y2)
= mappend (xL + yL, xR + yR) (zL, zR)
-- mappend (x1, y1) (x2 , y2) = (x1 + x2, y1 + y2)
= mappend ((xL + yL) + zL, (xR + yR) + zR)
-- (x + y) + z = x + (y + z)
= mappend (xL + (yL + zL), xR + (yR + zR))
-- mappend (x1, y1) (x2, y2) = (x1 + x2, y1 + y2)
= mappend (xL, xR) (yL + zL, yR + zR)
-- mappend (x1, y1) (x2, y2) = (x1 + x2, y1 + y2)
= mappend (xL, xR) (mappend (yL, yR) (zL, zR))
-- x = (xL, xR)
-- y = (yL, yR)
-- z = (zL, zR)
= mappend x (mappend y z)
-- x <> y = mappend x y
= x <> (y <> z)
```

That completes the proof of the three `Monoid`

laws, but I'm not satisfied with these proofs.

#### Generalizing proofs

I don't like the above proofs because they are disposable, meaning that I cannot reuse them to prove other properties of interest. I'm a programmer, so I loathe busy work and unnecessary repetition, both for code and proofs. I would like to find a way to generalize the above proofs so that I can use them in more places.

We improve proof reuse in the same way that we improve code reuse. To see why, consider the following `sort`

function:

`sort :: [Int] -> [Int]`

This `sort`

function is disposable because it only works on `Int`

s. For example, I cannot use the above function to `sort`

a list of `Double`

s.

Fortunately, programming languages with generics let us generalize `sort`

by parametrizing `sort`

on the element type of the list:

`sort :: Ord a => [a] -> [a]`

That type says that we can call `sort`

on any list of `a`

s, so long as the type `a`

implements the `Ord`

type class (a comparison interface). This works because `sort`

doesn't really care whether or not the elements are `Int`

s; `sort`

only cares if they are comparable.

Similarly, we can make the proof more "generic". If we inspect the proof closely, we will notice that we don't really care whether or not the tuple contains `Int`

s. The only `Int`

-specific properties we use in our proof are:

```
0 + x = x
x + 0 = x
(x + y) + z = x + (y + z)
```

However, these properties hold true for all `Monoid`

s, not just `Int`

s. Therefore, we can generalize our `Monoid`

instance for tuples by parametrizing it on the type of each field of the tuple:

```
instance (Monoid a, Monoid b) => Monoid (a, b) where
mempty = (mempty, mempty)
mappend (x1, y1) (x2, y2) = (mappend x1 x2, mappend y1 y2)
```

The above `Monoid`

instance says that we can combine tuples so long as we can combine their individual fields. Our original `Monoid`

instance was just a special case of this instance where both the `a`

and `b`

types are `Int`

s.

Note: The `mempty`

and `mappend`

on the left-hand side of each equation are for tuples. The `mempty`

s and `mappend`

s on the right-hand side of each equation are for the types `a`

and `b`

. Haskell overloads type class methods like `mempty`

and `mappend`

to work on any type that implements the `Monoid`

type class, and the compiler distinguishes them by their inferred types.

We can similarly generalize our original proofs, too, by just replacing the `Int`

-specific parts with their more general `Monoid`

counterparts.

Here is the generalized proof of the left identity law:

```
-- Left-hand side of the equation
mempty <> x
-- x <> y = mappend x y
= mappend mempty x
-- `mempty = (mempty, mempty)`
= mappend (mempty, mempty) x
-- Define: x = (xL, xR), since `x` is a tuple
= mappend (mempty, mempty) (xL, xR)
-- mappend (x1, y1) (x2, y2) = (mappend x1 x2, mappend y1 y2)
= (mappend mempty xL, mappend mempty xR)
-- Monoid law: mappend mempty x = x
= (xL, xR)
-- x = (xL, xR)
= x
```

... the right identity law:

```
-- Left-hand side of the equation
= x <> mempty
-- x <> y = mappend x y
= mappend x mempty
-- mempty = (mempty, mempty)
= mappend x (mempty, mempty)
-- Define: x = (xL, xR), since `x` is a tuple
= mappend (xL, xR) (mempty, mempty)
-- mappend (x1, y1) (x2, y2) = (mappend x1 x2, mappend y1 y2)
= (mappend xL mempty, mappend xR mempty)
-- Monoid law: mappend x mempty = x
= (xL, xR)
-- x = (xL, xR)
= x
```

... and the associativity law:

```
-- Left-hand side
(x <> y) <> z
-- x <> y = mappend x y
= mappend (mappend x y) z
-- x = (xL, xR)
-- y = (yL, yR)
-- z = (zL, zR)
= mappend (mappend (xL, xR) (yL, yR)) (zL, zR)
-- mappend (x1, y1) (x2 , y2) = (mappend x1 x2, mappend y1 y2)
= mappend (mappend xL yL, mappend xR yR) (zL, zR)
-- mappend (x1, y1) (x2 , y2) = (mappend x1 x2, mappend y1 y2)
= (mappend (mappend xL yL) zL, mappend (mappend xR yR) zR)
-- Monoid law: mappend (mappend x y) z = mappend x (mappend y z)
= (mappend xL (mappend yL zL), mappend xR (mappend yR zR))
-- mappend (x1, y1) (x2, y2) = (mappend x1 x2, mappend y1 y2)
= mappend (xL, xR) (mappend yL zL, mappend yR zR)
-- mappend (x1, y1) (x2, y2) = (mappend x1 x2, mappend y1 y2)
= mappend (xL, xR) (mappend (yL, yR) (zL, zR))
-- x = (xL, xR)
-- y = (yL, yR)
-- z = (zL, zR)
= mappend x (mappend y z)
-- x <> y = mappend x y
= x <> (y <> z)
```

This more general `Monoid`

instance lets us stick any `Monoid`

s inside the tuple fields and we can still combine the tuples. For example, lists form a `Monoid`

:

```
-- Exercise: Prove the monoid laws for lists
instance Monoid [a] where
mempty = []
mappend = (++)
```

... so we can stick lists inside the right field of each tuple and still combine them:

```
>>> (1, [2, 3]) <> (4, [5, 6])
(5, [2, 3, 5, 6])
>>> (1, [2, 3]) <> (4, mempty) <> (mempty, [5, 6])
(5, [2, 3, 5, 6])
>>> (1, [2, 3]) <> mempty <> (4, [5, 6])
(5, [2, 3, 5, 6])
```

Why, we can even stick yet another tuple inside the right field and still combine them:

```
>>> (1, (2, 3)) <> (4, (5, 6))
(5, (7, 9))
```

We can try even more exotic permutations and everything still "just works":

```
>>> ((1,[2, 3]), ([4, 5], 6)) <> ((7, [8, 9]), ([10, 11), 12)
((8, [2, 3, 8, 9]), ([4, 5, 10, 11], 18))
```

This is our first example of a "scalable proof". We began from three primitive building blocks:

`Int`

is a`Monoid`

`[a]`

is a`Monoid`

`(a, b)`

is a`Monoid`

if`a`

is a`Monoid`

and`b`

is a`Monoid`

... and we connected those three building blocks to assemble a variety of new `Monoid`

instances. No matter how many tuples we nest the result is still a `Monoid`

and obeys the `Monoid`

laws. We don't need to re-prove the `Monoid`

laws every time we assemble a new permutation of these building blocks.

However, these building blocks are still pretty limited. What other useful things can we combine to build new `Monoid`

s?

#### IO

We're so used to thinking of `Monoid`

s as data, so let's define a new `Monoid`

instance for something entirely un-data-like:

```
-- See "Appendix A" for some caveats
instance Monoid b => Monoid (IO b) where
mempty = return mempty
mappend io1 io2 = do
a1 <- io1
a2 <- io2
return (mappend a1 a2)
```

The above instance says: "If `a`

is a `Monoid`

, then an `IO`

action that returns an `a`

is also a `Monoid`

". Let's test this using the `getLine`

function from the `Prelude`

:

```
-- Read one line of input from stdin
getLine :: IO String
```

`String`

is a `Monoid`

, since a `String`

is just a list of characters, so we should be able to `mappend`

multiple `getLine`

statements together. Let's see what happens:

```
>>> getLine -- Reads one line of input
Hello<Enter>
"Hello"
>>> getLine <> getLine
ABC<Enter>
DEF<Enter>
"ABCDEF"
>>> getLine <> getLine <> getLine
1<Enter>
23<Enter>
456<Enter>
"123456"
```

Neat! When we combine multiple commands we combine their effects and their results.

Of course, we don't have to limit ourselves to reading strings. We can use `readLn`

from the Prelude to read in anything that implements the `Read`

type class:

```
-- Parse a `Read`able value from one line of stdin
readLn :: Read a => IO a
```

All we have to do is tell the compiler which type `a`

we intend to `Read`

by providing a type signature:

```
>>> readLn :: IO (Int, Int)
(1, 2)<Enter>
(1 ,2)
>>> readLn <> readLn :: IO (Int, Int)
(1,2)<Enter>
(3,4)<Enter>
(4,6)
>>> readLn <> readLn <> readLn :: IO (Int, Int)
(1,2)<Enter>
(3,4)<Enter>
(5,6)<Enter>
(9,12)
```

This works because:

`Int`

is a`Monoid`

- Therefore,
`(Int, Int)`

is a`Monoid`

- Therefore,
`IO (Int, Int)`

is a`Monoid`

Or let's flip things around and nest `IO`

actions inside of a tuple:

```
>>> let ios = (getLine, readLn) :: (IO String, IO (Int, Int))
>>> let (getLines, readLns) = ios <> ios <> ios
>>> getLines
1<Enter>
23<Enter>
456<Enter>
123456
>>> readLns
(1,2)<Enter>
(3,4)<Enter>
(5,6)<Enter>
(9,12)
```

We can very easily reason that the type `(IO String, IO (Int, Int))`

obeys the `Monoid`

laws because:

`String`

is a`Monoid`

- If
`String`

is a`Monoid`

then`IO String`

is also a`Monoid`

`Int`

is a`Monoid`

- If
`Int`

is a`Monoid`

, then`(Int, Int)`

is also a `Monoid - If
`(Int, Int)`

is a`Monoid`

, then`IO (Int, Int)`

is also a`Monoid`

- If
`IO String`

is a`Monoid`

and`IO (Int, Int)`

is a`Monoid`

, then`(IO String, IO (Int, Int))`

is also a`Monoid`

However, we don't really have to reason about this at all. The compiler will automatically assemble the correct `Monoid`

instance for us. The only thing we need to verify is that the primitive `Monoid`

instances obey the `Monoid`

laws, and then we can trust that any larger `Monoid`

instance the compiler derives will also obey the `Monoid`

laws.

#### The Unit Monoid

Haskell Prelude also provides the `putStrLn`

function, which echoes a `String`

to standard output with a newline:

`putStrLn :: String -> IO ()`

Is `putStrLn`

combinable? There's only one way to find out!

```
>>> putStrLn "Hello" <> putStrLn "World"
Hello
World
```

Interesting, but why does that work? Well, let's look at the types of the commands we are combining:

```
putStrLn "Hello" :: IO ()
putStrLn "World" :: IO ()
```

Well, we said that `IO b`

is a `Monoid`

if `b`

is a `Monoid`

, and `b`

in this case is `()`

(pronounced "unit"), which you can think of as an "empty tuple". Therefore, `()`

must form a `Monoid`

of some sort, and if we dig into `Data.Monoid`

, we will discover the following `Monoid`

instance:

```
-- Exercise: Prove the monoid laws for `()`
instance Monoid () where
mempty = ()
mappend () () = ()
```

This says that empty tuples form a trivial `Monoid`

, since there's only one possible value (ignoring bottom) for an empty tuple: `()`

. Therefore, we can derive that `IO ()`

is a `Monoid`

because `()`

is a `Monoid`

.

#### Functions

Alright, so we can combine `putStrLn "Hello"`

with `putStrLn "World"`

, but can we combine naked `putStrLn`

functions?

```
>>> (putStrLn <> putStrLn) "Hello"
Hello
Hello
```

Woah, how does that work?

We never wrote a `Monoid`

instance for the type `String -> IO ()`

, yet somehow the compiler magically accepted the above code and produced a sensible result.

This works because of the following `Monoid`

instance for functions:

```
instance Monoid b => Monoid (a -> b) where
mempty = \_ -> mempty
mappend f g = \a -> mappend (f a) (g a)
```

This says: "If `b`

is a `Monoid`

, then any function that returns a `b`

is also a `Monoid`

".

The compiler then deduced that:

`()`

is a`Monoid`

- If
`()`

is a`Monoid`

, then`IO ()`

is also a`Monoid`

- If
`IO ()`

is a`Monoid`

then`String -> IO ()`

is also a`Monoid`

The compiler is a trusted friend, deducing `Monoid`

instances we never knew existed.

#### Monoid plugins

Now we have enough building blocks to assemble a non-trivial example. Let's build a key logger with a `Monoid`

-based plugin system.

The central scaffold of our program is a simple `main`

loop that echoes characters from standard input to standard output:

```
main = do
hSetEcho stdin False
forever $ do
c <- getChar
putChar c
```

However, we would like to intercept key strokes for nefarious purposes, so we will slightly modify this program to install a handler at the beginning of the program that we will invoke on every incoming character:

```
install :: IO (Char -> IO ())
install = ???
main = do
hSetEcho stdin False
handleChar <- install
forever $ do
c <- getChar
handleChar c
putChar c
```

Notice that the type of `install`

is exactly the correct type to be a `Monoid`

:

`()`

is a`Monoid`

- Therefore,
`IO ()`

is also a`Monoid`

- Therefore
`Char -> IO ()`

is also a`Monoid`

- Therefore
`IO (Char -> IO ())`

is also a`Monoid`

Therefore, we can combine key logging plugins together using `Monoid`

operations. Here is one such example:

```
type Plugin = IO (Char -> IO ())
logTo :: FilePath -> Plugin
logTo filePath = do
handle <- openFile filePath WriteMode
hSetBuffering handle NoBuffering
return (hPutChar handle)
main = do
hSetEcho stdin False
handleChar <- logTo "file1.txt" <> logTo "file2.txt"
forever $ do
c <- getChar
handleChar c
putChar c
```

Now, every key stroke will be recorded to both `file1.txt`

and `file2.txt`

. Let's confirm that this works as expected:

```
$ ./logger
Test<Enter>
ABC<Enter>
42<Enter>
<Ctrl-C>
$ cat file1.txt
Test
ABC
42
$ cat file2.txt
Test
ABC
42
```

Try writing your own `Plugin`

s and mixing them in with `(<>)`

to see what happens. "Appendix C" contains the complete code for this section so you can experiment with your own `Plugin`

s.

#### Applicatives

Notice that I never actually proved the `Monoid`

laws for the following two `Monoid`

instances:

```
instance Monoid b => Monoid (a -> b) where
mempty = \_ -> mempty
mappend f g = \a -> mappend (f a) (g a)
instance Monoid a => Monoid (IO a) where
mempty = return mempty
mappend io1 io2 = do
a1 <- io1
a2 <- io2
return (mappend a1 a2)
```

The reason why is that they are both special cases of a more general pattern. We can detect the pattern if we rewrite both of them to use the `pure`

and `liftA2`

functions from `Control.Applicative`

:

```
import Control.Applicative (pure, liftA2)
instance Monoid b => Monoid (a -> b) where
mempty = pure mempty
mappend = liftA2 mappend
instance Monoid b => Monoid (IO b) where
mempty = pure mempty
mappend = liftA2 mappend
```

This works because both `IO`

and functions implement the following `Applicative`

interface:

```
class Functor f => Applicative f where
pure :: a -> f a
(<*>) :: f (a -> b) -> f a -> f b
-- Lift a binary function over the functor `f`
liftA2 :: Applicative f => (a -> b -> c) -> f a -> f b -> f c
liftA2 f x y = (pure f <*> x) <*> y
```

... and all `Applicative`

instances must obey several `Applicative`

laws:

```
pure id <*> v = v
((pure (.) <*> u) <*> v) <*> w = u <*> (v <*> w)
pure f <*> pure x = pure (f x)
u <*> pure x = pure (\f -> f y) <*> u
```

These laws may seem a bit adhoc, but this paper explains that you can reorganize the `Applicative`

class to this equivalent type class:

```
class Functor f => Monoidal f where
unit :: f ()
(#) :: f a -> f b -> f (a, b)
```

Then the corresponding laws become much more symmetric:

```
fmap snd (unit # x) = x -- Left identity
fmap fst (x # unit) = x -- Right identity
fmap assoc ((x # y) # z) = x # (y # z) -- Associativity
where
assoc ((a, b), c) = (a, (b, c))
fmap (f *** g) (x # y) = fmap f x # fmap g y -- Naturality
where
(f *** g) (a, b) = (f a, g b)
```

I personally prefer the `Monoidal`

formulation, but you go to war with the army you have, so we will use the `Applicative`

type class for this post.

All `Applicative`

s possess a very powerful property: they can all automatically lift `Monoid`

operations using the following instance:

```
instance (Applicative f, Monoid b) => Monoid (f b) where
mempty = pure mempty
mappend = liftA2 mappend
```

This says: "If `f`

is an `Applicative`

and `b`

is a `Monoid`

, then `f b`

is also a `Monoid`

." In other words, we can automatically extend any existing `Monoid`

with some new feature `f`

and get back a new `Monoid`

.

Note: The above instance is bad Haskell because it overlaps with other type class instances. In practice we have to duplicate the above code once for each `Applicative`

. Also, for some `Applicative`

s we may want a different `Monoid`

instance.

We can prove that the above instance obeys the `Monoid`

laws without knowing anything about `f`

and `b`

, other than the fact that `f`

obeys the `Applicative`

laws and `b`

obeys the `Applicative`

laws. These proofs are a little long, so I've included them in Appendix B.

Both `IO`

and functions implement the `Applicative`

type class:

```
instance Applicative IO where
pure = return
iof <*> iox = do
f <- iof
x <- iox
return (f x)
instance Applicative ((->) a) where
pure x = \_ -> x
kf <*> kx = \a ->
let f = kf a
x = kx a
in f x
```

This means that we can kill two birds with one stone. Every time we prove the `Applicative`

laws for some functor `F`

:

`instance Applicative F where ...`

... we automatically prove that the following `Monoid`

instance is correct for free:

```
instance Monoid b => Monoid (F b) where
mempty = pure mempty
mappend = liftA2 mappend
```

In the interest of brevity, I will skip the proofs of the `Applicative`

laws, but I may cover them in a subsequent post.

The beauty of `Applicative`

`Functor`

s is that every new `Applicative`

instance we discover adds a new building block to our `Monoid`

toolbox, and Haskell programmers have already discovered lots of `Applicative`

`Functor`

s.

#### Revisiting tuples

One of the very first `Monoid`

instances we wrote was:

```
instance (Monoid a, Monoid b) => Monoid (a, b) where
mempty = (mempty, mempty)
mappend (x1, y1) (x2, y2) = (mappend x1 x2, mappend y1 y2)
```

Check this out:

```
instance (Monoid a, Monoid b) => Monoid (a, b) where
mempty = pure mempty
mappend = liftA2 mappend
```

This `Monoid`

instance is yet another special case of the `Applicative`

pattern we just covered!

This works because of the following `Applicative`

instance in `Control.Applicative`

:

```
instance Monoid a => Applicative ((,) a) where
pure b = (mempty, b)
(a1, f) <*> (a2, x) = (mappend a1 a2, f x)
```

This instance obeys the `Applicative`

laws (proof omitted), so our `Monoid`

instance for tuples is automatically correct, too.

#### Composing applicatives

In the very first section I wrote:

Haskell programmers prove large-scale properties exactly the same way we build large-scale programs:

- We build small proofs that we can verify correct in isolation
- We compose smaller proofs into larger proofs

I don't like to use the word compose lightly. In the context of category theory, compose has a very rigorous meaning, indicating composition of morphisms in some category. This final section will show that we can actually compose `Monoid`

proofs in a very rigorous sense of the word.

We can define a category of `Monoid`

proofs:

- Objects are types and their associated
`Monoid`

proofs - Morphisms are
`Applicative`

`Functor`

s - The identity morphism is the
`Identity`

applicative - The composition operation is composition of
`Applicative`

`Functor`

s - The category laws are isomorphisms instead of equalities

So in our `Plugin`

example, we began on the proof that `()`

was a `Monoid`

and then composed three `Applicative`

morphisms to prove that `Plugin`

was a `Monoid`

. I will use the following diagram to illustrate this:

```
+-----------------------+
| |
| Legend: * = Object |
| |
| v |
| | = Morphism |
| v |
| |
+-----------------------+
* `()` is a `Monoid`
v
| IO
v
* `IO ()` is a `Monoid`
v
| ((->) String)
v
* `String -> IO ()` is a `Monoid`
v
| IO
v
* `IO (String -> IO ())` (i.e. `Plugin`) is a `Monoid`
```

Therefore, we were literally composing proofs together.

#### Conclusion

You can equationally reason at scale by decomposing larger proofs into smaller reusable proofs, the same way we decompose programs into smaller and more reusable components. There is no limit to how many proofs you can compose together, and therefore there is no limit to how complex of a program you can tame using equational reasoning.

This post only gave one example of composing proofs within Haskell. The more you learn the language, the more examples of composable proofs you will encounter. Another common example is automatically deriving `Monad`

proofs by composing monad transformers.

As you learn Haskell, you will discover that the hard part is not proving things. Rather, the challenge is learning how to decompose proofs into smaller proofs and you can cultivate this skill by studying category theory and abstract algebra. These mathematical disciplines teach you how to extract common and reusable proofs and patterns from what appears to be disposable and idiosyncratic code.

#### Appendix A - Missing `Monoid`

instances

These `Monoid`

instance from this post do not actually appear in the Haskell standard library:

```
instance Monoid b => Monoid (IO b)
instance Monoid Int
```

The first instance was recently proposed here on the Glasgow Haskell Users mailing list. However, in the short term you can work around it by writing your own `Monoid`

instances by hand just by inserting a sufficient number of `pure`

s and `liftA2`

s.

For example, suppose we wanted to provide a `Monoid`

instance for `Plugin`

. We would just newtype `Plugin`

and write:

```
newtype Plugin = Plugin { install :: IO (String -> IO ()) }
instance Monoid Plugin where
mempty = Plugin (pure (pure (pure mempty)))
mappend (Plugin p1) (Plugin p2) =
Plugin (liftA2 (liftA2 (liftA2 mappend)) p1 p2)
```

This is what the compiler would have derived by hand.

Alternatively, you could define an orphan `Monoid`

instance for `IO`

, but this is generally frowned upon.

There is no default `Monoid`

instance for `Int`

because there are actually two possible instances to choose from:

```
-- Alternative #1
instance Monoid Int where
mempty = 0
mappend = (+)
-- Alternative #2
instance Monoid Int where
mempty = 1
mappend = (*)
```

So instead, `Data.Monoid`

sidesteps the issue by providing two newtypes to distinguish which instance we prefer:

```
newtype Sum a = Sum { getSum :: a }
instance Num a => Monoid (Sum a)
newtype Product a = Product { getProduct :: a}
instance Num a => Monoid (Product a)
```

An even better solution is to use a semiring, which allows two `Monoid`

instances to coexist for the same type. You can think of Haskell's `Num`

class as an approximation of the semiring class:

```
class Num a where
fromInteger :: Integer -> a
(+) :: a -> a -> a
(*) :: a -> a -> a
-- ... and other operations unrelated to semirings
```

Note that we can also lift the `Num`

class over the `Applicative`

class, exactly the same way we lifted the `Monoid`

class. Here's the code:

```
instance (Applicative f, Num a) => Num (f a) where
fromInteger n = pure (fromInteger n)
(+) = liftA2 (+)
(*) = liftA2 (*)
(-) = liftA2 (-)
negate = fmap negate
abs = fmap abs
signum = fmap signum
```

This lifting guarantees that if `a`

obeys the semiring laws then so will `f a`

. Of course, you will have to specialize the above instance to every concrete `Applicative`

because otherwise you will get overlapping instances.

#### Appendix B

These are the proofs to establish that the following `Monoid`

instance obeys the `Monoid`

laws:

```
instance (Applicative f, Monoid b) => Monoid (f b) where
mempty = pure mempty
mappend = liftA2 mappend
```

... meaning that if `f`

obeys the `Applicative`

laws and `b`

obeys the `Monoid`

laws, then `f b`

also obeys the `Monoid`

laws.

Proof of the left identity law:

```
mempty <> x
-- x <> y = mappend x y
= mappend mempty x
-- mappend = liftA2 mappend
= liftA2 mappend mempty x
-- mempty = pure mempty
= liftA2 mappend (pure mempty) x
-- liftA2 f x y = (pure f <*> x) <*> y
= (pure mappend <*> pure mempty) <*> x
-- Applicative law: pure f <*> pure x = pure (f x)
= pure (mappend mempty) <*> x
-- Eta conversion
= pure (\a -> mappend mempty a) <*> x
-- mappend mempty x = x
= pure (\a -> a) <*> x
-- id = \x -> x
= pure id <*> x
-- Applicative law: pure id <*> v = v
= x
```

Proof of the right identity law:

```
x <> mempty = x
-- x <> y = mappend x y
= mappend x mempty
-- mappend = liftA2 mappend
= liftA2 mappend x mempty
-- mempty = pure mempty
= liftA2 mappend x (pure mempty)
-- liftA2 f x y = (pure f <*> x) <*> y
= (pure mappend <*> x) <*> pure mempty
-- Applicative law: u <*> pure y = pure (\f -> f y) <*> u
= pure (\f -> f mempty) <*> (pure mappend <*> x)
-- Applicative law: ((pure (.) <*> u) <*> v) <*> w = u <*> (v <*> w)
= ((pure (.) <*> pure (\f -> f mempty)) <*> pure mappend) <*> x
-- Applicative law: pure f <*> pure x = pure (f x)
= (pure ((.) (\f -> f mempty)) <*> pure mappend) <*> x
-- Applicative law : pure f <*> pure x = pure (f x)
= pure ((.) (\f -> f mempty) mappend) <*> x
-- `(.) f g` is just prefix notation for `f . g`
= pure ((\f -> f mempty) . mappend) <*> x
-- f . g = \x -> f (g x)
= pure (\x -> (\f -> f mempty) (mappend x)) <*> x
-- Apply the lambda
= pure (\x -> mappend x mempty) <*> x
-- Monoid law: mappend x mempty = x
= pure (\x -> x) <*> x
-- id = \x -> x
= pure id <*> x
-- Applicative law: pure id <*> v = v
= x
```

Proof of the associativity law:

```
(x <> y) <> z
-- x <> y = mappend x y
= mappend (mappend x y) z
-- mappend = liftA2 mappend
= liftA2 mappend (liftA2 mappend x y) z
-- liftA2 f x y = (pure f <*> x) <*> y
= (pure mappend <*> ((pure mappend <*> x) <*> y)) <*> z
-- Applicative law: ((pure (.) <*> u) <*> v) <*> w = u <*> (v <*> w)
= (((pure (.) <*> pure mappend) <*> (pure mappend <*> x)) <*> y) <*> z
-- Applicative law: pure f <*> pure x = pure (f x)
= ((pure f <*> (pure mappend <*> x)) <*> y) <*> z
where
f = (.) mappend
-- Applicative law: ((pure (.) <*> u) <*> v) <*> w = u <*> (v <*> w)
= ((((pure (.) <*> pure f) <*> pure mappend) <*> x) <*> y) <*> z
where
f = (.) mappend
-- Applicative law: pure f <*> pure x = pure (f x)
= (((pure f <*> pure mappend) <*> x) <*> y) <*> z
where
f = (.) ((.) mappend)
-- Applicative law: pure f <*> pure x = pure (f x)
= ((pure f <*> x) <*> y) <*> z
where
f = (.) ((.) mappend) mappend
-- (.) f g = f . g
= ((pure f <*> x) <*> y) <*> z
where
f = ((.) mappend) . mappend
-- Eta conversion
= ((pure f <*> x) <*> y) <*> z
where
f x = (((.) mappend) . mappend) x
-- (f . g) x = f (g x)
= ((pure f <*> x) <*> y) <*> z
where
f x = (.) mappend (mappend x)
-- (.) f g = f . g
= ((pure f <*> x) <*> y) <*> z
where
f x = mappend . (mappend x)
-- Eta conversion
= ((pure f <*> x) <*> y) <*> z
where
f x y = (mappend . (mappend x)) y
-- (f . g) x = f (g x)
= ((pure f <*> x) <*> y) <*> z
where
f x y = mappend (mappend x y)
-- Eta conversion
= ((pure f <*> x) <*> y) <*> z
where
f x y z = mappend (mappend x y) z
-- Monoid law: mappend (mappend x y) z = mappend x (mappend y z)
= ((pure f <*> x) <*> y) <*> z
where
f x y z = mappend x (mappend y z)
-- (f . g) x = f (g x)
= ((pure f <*> x) <*> y) <*> z
where
f x y z = (mappend x . mappend y) z
-- Eta conversion
= ((pure f <*> x) <*> y) <*> z
where
f x y = mappend x . mappend y
-- (.) f g = f . g
= ((pure f <*> x) <*> y) <*> z
where
f x y = (.) (mappend x) (mappend y)
-- (f . g) x = f
= ((pure f <*> x) <*> y) <*> z
where
f x y = (((.) . mappend) x) (mappend y)
-- (f . g) x = f (g x)
= ((pure f <*> x) <*> y) <*> z
where
f x y = ((((.) . mappend) x) . mappend) y
-- Eta conversion
= ((pure f <*> x) <*> y) <*> z
where
f x = (((.) . mappend) x) . mappend
-- (.) f g = f . g
= ((pure f <*> x) <*> y) <*> z
where
f x = (.) (((.) . mappend) x) mappend
-- Lambda abstraction
= ((pure f <*> x) <*> y) <*> z
where
f x = (\k -> k mappend) ((.) (((.) . mappend) x))
-- (f . g) x = f (g x)
= ((pure f <*> x) <*> y) <*> z
where
f x = (\k -> k mappend) (((.) . ((.) . mappend)) x)
-- Eta conversion
= ((pure f <*> x) <*> y) <*> z
where
f = (\k -> k mappend) . ((.) . ((.) . mappend))
-- (.) f g = f . g
= ((pure f <*> x) <*> y) <*> z
where
f = (.) (\k -> k mappend) ((.) . ((.) . mappend))
-- Applicative law: pure f <*> pure x = pure (f x)
= (((pure g <*> pure f) <*> x) <*> y) <*> z
where
g = (.) (\k -> k mappend)
f = (.) . ((.) . mappend)
-- Applicative law: pure f <*> pure x = pure (f x)
= ((((pure (.) <*> pure (\k -> k mappend)) <*> pure f) <*> x) <*> y) <*> z
where
f = (.) . ((.) . mappend)
-- Applicative law: ((pure (.) <*> u) <*> v) <*> w = u <*> (v <*> w)
= ((pure (\k -> k mappend) <*> (pure f <*> x)) <*> y) <*> z
where
f = (.) . ((.) . mappend)
-- u <*> pure y = pure (\k -> k y) <*> u
= (((pure f <*> x) <*> pure mappend) <*> y) <*> z
where
f = (.) . ((.) . mappend)
-- (.) f g = f . g
= (((pure f <*> x) <*> pure mappend) <*> y) <*> z
where
f = (.) (.) ((.) . mappend)
-- Applicative law: pure f <*> pure x = pure (f x)
= ((((pure g <*> pure f) <*> x) <*> pure mappend) <*> y) <*> z
where
g = (.) (.)
f = (.) . mappend
-- Applicative law: pure f <*> pure x = pure (f x)
= (((((pure (.) <*> pure (.)) <*> pure f) <*> x) <*> pure mappend) <*> y) <*> z
where
f = (.) . mappend
-- Applicative law: ((pure (.) <*> u) <*> v) <*> w = u <*> (v <*> w)
= (((pure (.) <*> (pure f <*> x)) <*> pure mappend) <*> y) <*> z
where
f = (.) . mappend
-- Applicative law: ((pure (.) <*> u) <*> v) <*> w = u <*> (v <*> w)
= ((pure f <*> x) <*> (pure mappend <*> y)) <*> z
where
f = (.) . mappend
-- (.) f g = f . g
= ((pure f <*> x) <*> (pure mappend <*> y)) <*> z
where
f = (.) (.) mappend
-- Applicative law: pure f <*> pure x = pure (f x)
= (((pure f <*> pure mappend) <*> x) <*> (pure mappend <*> y)) <*> z
where
f = (.) (.)
-- Applicative law: pure f <*> pure x = pure (f x)
= ((((pure (.) <*> pure (.)) <*> pure mappend) <*> x) <*> (pure mappend <*> y)) <*> z
-- Applicative law: ((pure (.) <*> u) <*> v) <*> w = u <*> (v <*> w)
= ((pure (.) <*> (pure mappend <*> x)) <*> (pure mappend <*> y)) <*> z
-- Applicative law: ((pure (.) <*> u) <*> v) <*> w = u <*> (v <*> w)
= (pure mappend <*> x) <*> ((pure mappend <*> y) <*> z)
-- liftA2 f x y = (pure f <*> x) <*> y
= liftA2 mappend x (liftA2 mappend y z)
-- mappend = liftA2 mappend
= mappend x (mappend y z)
-- x <> y = mappend x y
= x <> (y <> z)
```

#### Appendix C: Monoid key logging

Here is the complete program for a key logger with a `Monoid`

-based plugin system:

```
import Control.Applicative (pure, liftA2)
import Control.Monad (forever)
import Data.Monoid
import System.IO
instance Monoid b => Monoid (IO b) where
mempty = pure mempty
mappend = liftA2 mappend
type Plugin = IO (Char -> IO ())
logTo :: FilePath -> Plugin
logTo filePath = do
handle <- openFile filePath WriteMode
hSetBuffering handle NoBuffering
return (hPutChar handle)
main = do
hSetEcho stdin False
handleChar <- logTo "file1.txt" <> logTo "file2.txt"
forever $ do
c <- getChar
handleChar c
putChar c
```